fix std::string constructed from nullptr

[xonotic/gmqcc.git] / tests / xor.qc

diff --git a/tests/xor.qc b/tests/xor.qc
index 41d02e95ee366a80a48fdb96975ed55d9a9d9267..fc3a4b5a89614e71b91119009c796c38b09ae9da 100644 (file)
--- a/tests/xor.qc
+++ b/tests/xor.qc
@@ -3,50 +3,75 @@ vector swap(float x, float y) {
     // everyone knows this trick
     ret.x = x;
     ret.y = y;
-    
+
     ret.x = ret.x ^ ret.y;
     ret.y = ret.y ^ ret.x;
     ret.x = ret.x ^ ret.y;
-    
+
     return ret;
 }
 
+float f(vector b) {
+    return b.x+b.y+b.z;
+}
+
 void main() {
     float x = 5;
     float y = 3;
     float z = x ^ y; // 6
-    
+
     float a = 2;
     float b = 10;
     float c = a ^ b; // 8
-    
+
     print(ftos(z), "\n");
     print(ftos(c), "\n");
-    
+
     // commutative?
     if (x ^ y == y ^ x)
         print("commutative\n");
-    
+
     // assocative?
     if (x ^ (y ^ z) == (x ^ y) ^ z)
         print("assocative\n");
-        
+
     // elements are their own inverse?
     if (x ^ 0 == x)
         print("inverse\n");
-        
+
     // vector ^ vector
     // vector ^ float
     // are legal in constant expressions (currently)
+    vector v1 = '5 2 5';
+    vector v2 = '3 10 3';
+
+    print("vv: ", vtos(v1 ^ v2), "\n");
+    print("vf: ", vtos(v1 ^ 10), "\n");
+
     const vector v3 = '5 2 5' ^ '3 10 3';
     const vector v4 = '5 2 5' ^ 10;
-    
+
     print("vv: ", vtos(v3), "\n");
     print("vf: ", vtos(v4), "\n");
-    
+
     // good olde xor swap test too
     float swap_x = 100;
     float swap_y = 200;
     vector swaps = swap(swap_x, swap_y);
     print("100:200 swapped is: ", ftos(swaps.x), ":", ftos(swaps.y), "\n");
+
+    // good olde xor swap test too
+    vector swap_u = '1 2 3';
+    vector swap_v = '4 5 6';
+    swap_u ^= swap_v;
+    swap_v ^= swap_u;
+    swap_u ^= swap_v;
+    print("'1 2 3':'4 5 6' swapped is: ", vtos(swap_u), ":", vtos(swap_v), "\n");
+
+    // the one that showed us overlap bugs
+    print(vtos('1 2 3' ^ f('3 2 1') ^ f('1 1 1')), "\n");
+    print(vtos('1 2 3' ^ f('3 2 1') ^ 3),          "\n");
+    print(vtos('1 2 3' ^ 6          ^ 3),          "\n");
+    print(vtos('1 2 3' ^ 6          ^ f('1 1 1')), "\n");
+    print(vtos('1 2 3' ^ 5),                       "\n");
 }